题目内容
脱式计算或解方程.
|
| 4-
| ||||||||||||||||||||
|
|
|
考点:分数的四则混合运算,分数的简便计算
专题:运算顺序及法则
分析:(1)运用加法结合律解答,
(2)(4)运用乘法分配律解答,
(3)运用减法性质解答,
(5)按照先算小括号里面的,再算中括号里面的,最后算括号外面的顺序计算解答,
(6)依据等式的性质,方程两边同时减
,再同时除以
即可求解.
(2)(4)运用乘法分配律解答,
(3)运用减法性质解答,
(5)按照先算小括号里面的,再算中括号里面的,最后算括号外面的顺序计算解答,
(6)依据等式的性质,方程两边同时减
| 1 |
| 4 |
| 3 |
| 4 |
解答:
解:(1)
+
×
+
=
+
+
=
+1
=1
;
(2)
×
+
÷7
=
×(
+
)
=
×1
=
;
(3)4-
÷
-
=4-(
+
)
=4-1
=3;
(4)
×(9+
)-
=
×9+
×
-
=8+(
-
)
=8+0
=8;
(5)
÷[(
-
)×
]
=
÷[(
×
]
=
÷
=1
;
(6)
x+
=
x+
-
=
-
x÷
=
÷
x=
.
| 3 |
| 8 |
| 4 |
| 5 |
| 5 |
| 6 |
| 1 |
| 3 |
=
| 3 |
| 8 |
| 2 |
| 3 |
| 1 |
| 3 |
=
| 3 |
| 8 |
=1
| 3 |
| 8 |
(2)
| 1 |
| 7 |
| 6 |
| 11 |
| 5 |
| 11 |
=
| 1 |
| 7 |
| 6 |
| 11 |
| 5 |
| 11 |
=
| 1 |
| 7 |
=
| 1 |
| 7 |
(3)4-
| 8 |
| 15 |
| 2 |
| 3 |
| 1 |
| 5 |
=4-(
| 4 |
| 5 |
| 1 |
| 5 |
=4-1
=3;
(4)
| 8 |
| 9 |
| 3 |
| 4 |
| 2 |
| 3 |
=
| 8 |
| 9 |
| 8 |
| 9 |
| 3 |
| 4 |
| 2 |
| 3 |
=8+(
| 2 |
| 3 |
| 2 |
| 3 |
=8+0
=8;
(5)
| 5 |
| 18 |
| 5 |
| 7 |
| 1 |
| 3 |
| 7 |
| 16 |
=
| 5 |
| 18 |
| 8 |
| 21 |
| 7 |
| 16 |
=
| 5 |
| 18 |
| 1 |
| 6 |
=1
| 2 |
| 3 |
(6)
| 3 |
| 4 |
| 1 |
| 4 |
| 3 |
| 8 |
| 3 |
| 4 |
| 1 |
| 4 |
| 1 |
| 4 |
| 3 |
| 8 |
| 1 |
| 4 |
| 3 |
| 4 |
| 3 |
| 4 |
| 1 |
| 8 |
| 3 |
| 4 |
x=
| 1 |
| 6 |
点评:(1)依据四则运算计算方法正确进行计算,(2)正确运用简便方法解决问题,是本题考查知识点.
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