题目内容
解方程
x-30%x=
8×(x-
)=
.
| 5 |
| 8 |
| 7 |
| 20 |
8×(x-
| 3 |
| 4 |
| 5 |
| 4 |
分析:(1)先计算
x-30%x,再根据等式的性质解方程即可;
(2)根据等式的性质2,可得x-
=
,再根据等式的性质1求解.
| 5 |
| 8 |
(2)根据等式的性质2,可得x-
| 3 |
| 4 |
| 5 |
| 32 |
解答:解:(1)
x-30%x=
x=
x÷
=
÷
x=
;
(2)8×(x-
)=
8×(x-
)÷8=
÷8
x-
+
=
+
x=
.
| 5 |
| 8 |
| 7 |
| 20 |
| 13 |
| 40 |
| 7 |
| 20 |
| 13 |
| 40 |
| 13 |
| 40 |
| 7 |
| 20 |
| 13 |
| 40 |
x=
| 14 |
| 13 |
(2)8×(x-
| 3 |
| 4 |
| 5 |
| 4 |
8×(x-
| 3 |
| 4 |
| 5 |
| 4 |
x-
| 3 |
| 4 |
| 3 |
| 4 |
| 5 |
| 32 |
| 3 |
| 4 |
x=
| 29 |
| 32 |
点评:考查了运用等式的性质解方程.等式的性质1:等式两边同时加上(或减去)同一个数(或式子),结果仍相等.等式的性质2:等式两边同时乘同一个数,或除以同一个不为0的数,结果仍相等.
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