题目内容
计算下列各题
| 3333×3333+9999×8889 | (
|
2007×
| ||||||||||||||||
|
(
|
|
分析:(1)(2)(3)(6)运用乘法分配律,
(4)按照先算第二级运算,再算第一级运算,如果只含有同一级运算,按照从左到右顺序就是,有括号先算括号里面的顺序解答,
(5)先运用乘法分配律,再运用加法结合律即可解答.
(4)按照先算第二级运算,再算第一级运算,如果只含有同一级运算,按照从左到右顺序就是,有括号先算括号里面的顺序解答,
(5)先运用乘法分配律,再运用加法结合律即可解答.
解答:解:(1)3333×3333+9999×8889,
=9999×1111+9999×8889,
=9999×(1111+8889),
=9999×10000,
=99990000;
(2)(
-
)×5×7,
=
×5×7-
×5×7,
=7-5,
=2;
(3)2007×
,
=2008×
-1×
,
=2007-
,
=2206
;
(4)
×[4÷(
-
)],
=
×[4÷
],
=
×
,
=1;
(5)(
+
)×7-21÷13,
=
×7+
×7-
,
=5+0,
=5;
(6)
÷8+
×
,
=(
+
)×
,
=1×
,
=
.
=9999×1111+9999×8889,
=9999×(1111+8889),
=9999×10000,
=99990000;
(2)(
| 1 |
| 5 |
| 1 |
| 7 |
=
| 1 |
| 5 |
| 1 |
| 7 |
=7-5,
=2;
(3)2007×
| 2007 |
| 2008 |
=2008×
| 2007 |
| 2008 |
| 2007 |
| 2008 |
=2007-
| 2007 |
| 2008 |
=2206
| 1 |
| 2008 |
(4)
| 11 |
| 60 |
| 4 |
| 3 |
| 3 |
| 5 |
=
| 11 |
| 60 |
| 11 |
| 15 |
=
| 11 |
| 60 |
| 60 |
| 11 |
=1;
(5)(
| 5 |
| 7 |
| 3 |
| 13 |
=
| 5 |
| 7 |
| 3 |
| 13 |
| 21 |
| 13 |
=5+0,
=5;
(6)
| 5 |
| 19 |
| 1 |
| 8 |
| 14 |
| 19 |
=(
| 5 |
| 19 |
| 14 |
| 19 |
| 1 |
| 8 |
=1×
| 1 |
| 8 |
=
| 1 |
| 8 |
点评:本题考查知识点:(1)正确选择并运用简便算法解决问题,(2)依据四则运算顺序正确进行计算.
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