题目内容
正确计算.
(1)0.008×0.000125+0.0125÷0.04=
(2)1-
-
-
-
=
.
(1)0.008×0.000125+0.0125÷0.04=
0.312501
0.312501
(2)1-
| 1 |
| 2 |
| 1 |
| 20 |
| 1 |
| 200 |
| 1 |
| 2000 |
| 889 |
| 2000 |
| 889 |
| 2000 |
分析:(1)先把0.0125根据除以一个数再乘上这个数,还是原数,从而变成0.000125,然后利用乘法的分配律进行计算;
(2)利用连续减去几个数等于减去这几个数的和进行计算.
(2)利用连续减去几个数等于减去这几个数的和进行计算.
解答:解:(1)0.008×0.000125+0.0125÷0.04,
=0.008×0.000125+0.000125×100÷0.04,
=0.000125×(0.008+100÷0.04),
=0.000125×(0.008+2500),
=0.000125×2500.008,
=0.312501;
(2)1-
-
-
-
,
=1-(
+
+
+
),
=1-(
+
+
+
),
=1-
,
=
.
故答案为:0.312501,
.
=0.008×0.000125+0.000125×100÷0.04,
=0.000125×(0.008+100÷0.04),
=0.000125×(0.008+2500),
=0.000125×2500.008,
=0.312501;
(2)1-
| 1 |
| 2 |
| 1 |
| 20 |
| 1 |
| 200 |
| 1 |
| 2000 |
=1-(
| 1 |
| 2 |
| 1 |
| 20 |
| 1 |
| 200 |
| 1 |
| 2000 |
=1-(
| 1000 |
| 2000 |
| 100 |
| 2000 |
| 10 |
| 2000 |
| 1 |
| 2000 |
=1-
| 1111 |
| 2000 |
=
| 889 |
| 2000 |
故答案为:0.312501,
| 889 |
| 2000 |
点评:此题考查了乘法的分配律和减法的简算方法.
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