题目内容
甲、乙、丙三个数,甲、乙的和比丙多59,乙、丙的和比甲多49,甲、丙的和比乙多85,求这三个数.
分析:用59加49加85就是这三个数的和,再减59,就是两个丙.同理可求出甲和乙.据此解答.
解答:解:丙数是:
(59+49+85-59)÷2,
=134÷2,
=67;
甲数是:
(59+49+85-49)÷2,
=144÷2,
=72;
乙数是:
(59+49+85-85)÷2,
=108÷2,
=54;
答:甲数是72,乙数是54,丙数是67.
(59+49+85-59)÷2,
=134÷2,
=67;
甲数是:
(59+49+85-49)÷2,
=144÷2,
=72;
乙数是:
(59+49+85-85)÷2,
=108÷2,
=54;
答:甲数是72,乙数是54,丙数是67.
点评:本题的关键是求出三个数的和,再分析数量关系,分别求出甲乙丙三个数.
练习册系列答案
相关题目