题目内容
找规律填空.
3050,3100,3150,3200, , .
9300,9200,9100, , , .
0.1,0.2,0.3, , .
,
,
, , .
3050,3100,3150,3200,
9300,9200,9100,
0.1,0.2,0.3,
| 6 |
| 7 |
| 5 |
| 7 |
| 4 |
| 7 |
考点:数列中的规律
专题:探索数的规律
分析:(1)3100-3050=50,3150-3100=50,3200-3150=50,后一个数比前一个数多50;
(2)9300-9200=100,9200-9100=100,后一个数比前一个数少100;
(3)0.2-0.1=0.1,0.3-0.2=0.1,后一个数比前一个数多0.1;
(4)
-
=
,
-
=
,前一个数比后一个数多
.
(2)9300-9200=100,9200-9100=100,后一个数比前一个数少100;
(3)0.2-0.1=0.1,0.3-0.2=0.1,后一个数比前一个数多0.1;
(4)
| 6 |
| 7 |
| 5 |
| 7 |
| 1 |
| 7 |
| 5 |
| 7 |
| 4 |
| 7 |
| 1 |
| 7 |
| 1 |
| 7 |
解答:
解:(1)3200+50=3250,
3250+50=3300;
(2)9100-100=9000,
9000-100=8900,
8900-100=8800;
(3)0.3+0.1=0.4,
0.4+0.1=0.5;
(4)
-
=
,
-
=
.
故答案为:3250,3300;9000,8900,8800;0.4,0.5;
,
.
3250+50=3300;
(2)9100-100=9000,
9000-100=8900,
8900-100=8800;
(3)0.3+0.1=0.4,
0.4+0.1=0.5;
(4)
| 4 |
| 7 |
| 1 |
| 7 |
| 3 |
| 7 |
| 3 |
| 7 |
| 1 |
| 7 |
| 2 |
| 7 |
故答案为:3250,3300;9000,8900,8800;0.4,0.5;
| 3 |
| 7 |
| 2 |
| 7 |
点评:本题找出相邻两个数的差不变,再根据这个差进行求解.
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