题目内容

计算:
10-
2
3
×10-
2
3
[1-(
1
4
+
3
8
)]÷
1
4
3
4
+
1
2
-
7
12
)×24
(19-
57
80
)÷19
17
24
×
3
4
+
17
24
÷4
2-
6
13
÷
9
26
-
2
3
χ÷
2
3
=
3
8
χ-
3
5
χ=12.
(1)10-
2
3
×10-
2
3

=10-
20
3
-
2
3

=10-(
20
3
+
2
3
),
=10-7
1
3

=2
2
3


(2)[1-(
1
4
+
3
8
)]÷
1
4

=[1-
5
8
1
4

=
3
8
÷
1
4

=
3
2


(3)(
3
4
+
1
2
-
7
12
)×24,
=
3
4
×24+
1
2
×24-
7
12
×24,
=18+12-14,
=16;

(4)(19-
57
80
)÷19,
=(19-
57
80
)×
1
19

=19×
1
19
-
57
80
×
1
19

=1-
3
80

=
77
80


(5)
17
24
×
3
4
+
17
24
÷4,
=
17
24
×
3
4
+
17
24
×
1
4

=(
3
4
+
1
4
)×
17
24

=1×
17
24

=
17
24


(6)2-
6
13
÷
9
26
-
2
3

=2-
4
3
-
2
3

=2-(
4
3
+
2
3
),
=2-2,
=0;

(7)χ÷
2
3
=
3
8

χ÷
2
3
×
2
3
=
3
8
×
2
3

x=
1
4


(8)χ-
3
5
χ=12,
2
5
x=12,
2
5
x÷
2
5
=12÷
2
5

x=30.
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