题目内容

用递等式计算
7
12
÷9+
1
9
×
5
12

[
4
5
-0÷(
1
3
+
2
5
)]×
5
8
(3.8-1.8÷2)×0.3
2
3
-
2
3
÷2
1
15
+
2
17
)×15×17
(15-15×
4
5
)×
7
24
(1)
7
12
÷9+
1
9
×
5
12

=
7
12
×
1
9
+
1
9
×
5
12

=(
7
12
+
5
12
)×
1
9

=1×
1
9

=
1
9


(2)[
4
5
-0÷(
1
3
+
2
5
)]×
5
8

=
4
5
×
5
8

=
1
2


(3)(3.8-1.8÷2)×0.3,
=(3.8-0.9)×0.3,
=2.9×0.3,
=0.87;

(4)2÷
2
3
-
2
3
÷2,
=3-
1
3

=2
2
3


(5)(
1
15
+
2
17
)×15×17,
=
1
15
×15×17+
2
17
×15×17

=17+30,
=47;

(6)(15-15×
4
5
)×
7
24

=(15-12)×
7
24

=3×
7
24

=
7
8
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