题目内容

用递等式计算
7
12
÷9+
1
9
×
5
12

[
4
5
-0÷(
1
3
+
2
5
)]×
5
8
(3.8-1.8÷2)×0.32÷
2
3
-
2
3
÷2
(
1
15
+
2
17
)×15×17
(15-15×
4
5
)×
7
24
.
(1)
7
12
÷9+
1
9
×
5
12
,
=
7
12
×
1
9
+
1
9
×
5
12
,
=(
7
12
+
5
12
)×
1
9
,
=1×
1
9
,
=
1
9
;

(2)[
4
5
-0÷(
1
3
+
2
5
)]×
5
8
,
=
4
5
×
5
8
,
=
1
2
;

(3)(3.8-1.8÷2)×0.3,
=(3.8-0.9)×0.3,
=2.9×0.3,
=0.87;

(4)2÷
2
3
-
2
3
÷2,
=3-
1
3
,
=2
2
3
;

(5)(
1
15
+
2
17
)×15×17,
=
1
15
×15×17+
2
17
×15×17
,
=17+30,
=47;

(6)(15-15×
4
5
)×
7
24
,
=(15-12)×
7
24
,
=3×
7
24
,
=
7
8
.
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