题目内容
用递等式计算
| [
| ||||||||||||||
| (3.8-1.8÷2)×0.3 | 2÷
| ||||||||||||||
(
| (15-15×
|
(1)
÷9+
×
,
=
×
+
×
,
=(
+
)×
,
=1×
,
=
;
(2)[
-0÷(
+
)]×
,
=
×
,
=
;
(3)(3.8-1.8÷2)×0.3,
=(3.8-0.9)×0.3,
=2.9×0.3,
=0.87;
(4)2÷
-
÷2,
=3-
,
=2
;
(5)(
+
)×15×17,
=
×15×17+
×15×17,
=17+30,
=47;
(6)(15-15×
)×
,
=(15-12)×
,
=3×
,
=
.
| 7 |
| 12 |
| 1 |
| 9 |
| 5 |
| 12 |
=
| 7 |
| 12 |
| 1 |
| 9 |
| 1 |
| 9 |
| 5 |
| 12 |
=(
| 7 |
| 12 |
| 5 |
| 12 |
| 1 |
| 9 |
=1×
| 1 |
| 9 |
=
| 1 |
| 9 |
(2)[
| 4 |
| 5 |
| 1 |
| 3 |
| 2 |
| 5 |
| 5 |
| 8 |
=
| 4 |
| 5 |
| 5 |
| 8 |
=
| 1 |
| 2 |
(3)(3.8-1.8÷2)×0.3,
=(3.8-0.9)×0.3,
=2.9×0.3,
=0.87;
(4)2÷
| 2 |
| 3 |
| 2 |
| 3 |
=3-
| 1 |
| 3 |
=2
| 2 |
| 3 |
(5)(
| 1 |
| 15 |
| 2 |
| 17 |
=
| 1 |
| 15 |
| 2 |
| 17 |
=17+30,
=47;
(6)(15-15×
| 4 |
| 5 |
| 7 |
| 24 |
=(15-12)×
| 7 |
| 24 |
=3×
| 7 |
| 24 |
=
| 7 |
| 8 |
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