题目内容
求未知数X.
|
1-
|
1÷(
|
考点:方程的解和解方程
专题:简易方程
分析:①先计算方程的左边,然后方程的两边同时乘以
即可得到未知数的值.
②方程的两边同时加上
x,然后方程的两边同时减去
方程的两边同时乘以
即可得到未知数的值.
③方程的两边同时乘以(
X-
),然后方程的两边同时加上
,再同时乘以
即可得到未知数的值.
| 15 |
| 7 |
②方程的两边同时加上
| 4 |
| 5 |
| 1 |
| 3 |
| 5 |
| 4 |
③方程的两边同时乘以(
| 4 |
| 5 |
| 1 |
| 5 |
| 3 |
| 5 |
| 5 |
| 12 |
解答:
解:①
X-
X=1
X=1
X×
=
X=2
②1-
X=
1+
X-
X=
+
X
X+
-
=1-
X=
X×
=
×
X=
③1÷(
X-
)=3
1×(
X-
)÷(
X-
)=3×(
X-
)
3×(
X-
)=1
X-
=1
X+
-
=1+
X=
X×
=
×
X=
| 2 |
| 3 |
| 1 |
| 5 |
| 7 |
| 15 |
| 7 |
| 15 |
| 15 |
| 7 |
| 15 |
| 7 |
X=2
| 1 |
| 7 |
②1-
| 4 |
| 5 |
| 1 |
| 3 |
1+
| 4 |
| 5 |
| 4 |
| 5 |
| 1 |
| 3 |
| 4 |
| 5 |
| 4 |
| 5 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 3 |
| 4 |
| 5 |
| 2 |
| 3 |
| 4 |
| 5 |
| 5 |
| 4 |
| 2 |
| 3 |
| 5 |
| 4 |
X=
| 5 |
| 6 |
③1÷(
| 4 |
| 5 |
| 1 |
| 5 |
1×(
| 4 |
| 5 |
| 1 |
| 5 |
| 4 |
| 5 |
| 1 |
| 5 |
| 4 |
| 5 |
| 1 |
| 5 |
3×(
| 4 |
| 5 |
| 1 |
| 5 |
| 12 |
| 5 |
| 3 |
| 5 |
| 12 |
| 5 |
| 3 |
| 5 |
| 3 |
| 5 |
| 3 |
| 5 |
| 12 |
| 5 |
| 8 |
| 5 |
| 12 |
| 5 |
| 5 |
| 12 |
| 8 |
| 5 |
| 5 |
| 12 |
X=
| 2 |
| 3 |
点评:本题运用等式的基本性质进行解答即可.
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