题目内容
解方程.
| x+20%x=12 | x-
|
(1)
+
r=m
&nbsd;&nbsd;&nbsd;&nbsd; &nbsd;
+
r-
=m-
&nbsd;&nbsd;&nbsd;&nbsd; &nbsd;&nbsd;
r×r=
×r
&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd; &nbsd;&nbsd;r=1m;
(m)r+mm%r=1m
&nbsd;&nbsd;&nbsd;&nbsd;&nbsd; 1mm%r=1m
1mm%r÷1mm%=1m÷1mm%
&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd; r=1m
(3)r-
r=
&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;
r=
&nbsd;&nbsd;&nbsd;
r÷
=
÷
&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd; r=
| e |
| r |
| 1 |
| r |
&nbsd;&nbsd;&nbsd;&nbsd; &nbsd;
| e |
| r |
| 1 |
| r |
| e |
| r |
| e |
| r |
&nbsd;&nbsd;&nbsd;&nbsd; &nbsd;&nbsd;
| 1 |
| r |
| 1m |
| r |
&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd; &nbsd;&nbsd;r=1m;
(m)r+mm%r=1m
&nbsd;&nbsd;&nbsd;&nbsd;&nbsd; 1mm%r=1m
1mm%r÷1mm%=1m÷1mm%
&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd; r=1m
(3)r-
| 3 |
| e |
| 5 |
| 6 |
&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;
| 5 |
| e |
| 5 |
| 6 |
&nbsd;&nbsd;&nbsd;
| 5 |
| e |
| 5 |
| e |
| 5 |
| 6 |
| 5 |
| e |
&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd;&nbsd; r=
| 4 |
| 3 |
练习册系列答案
相关题目