题目内容
给下面的算式添上括号,使算式能成立.
×
-
×
=0
-
×
-
=
.
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 3 |
| 1 |
| 30 |
| 1 |
| 6 |
考点:分数的四则混合运算
专题:运算顺序及法则
分析:(1)要使结果为0,需先算减法,由此添加括号改变运算顺序即可;
(2)因为
-
=
,而
×
-
=
,所以先算
×
-
=
添加括号即可.
(2)因为
| 1 |
| 5 |
| 1 |
| 30 |
| 1 |
| 6 |
| 1 |
| 5 |
| 1 |
| 3 |
| 1 |
| 30 |
| 1 |
| 30 |
| 1 |
| 5 |
| 1 |
| 3 |
| 1 |
| 30 |
| 1 |
| 30 |
解答:
解:(1)
×(
-
)×
=0;
(2)
-(
×
-
)
=
-(
-
)
=
-
=
.
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 4 |
(2)
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 3 |
| 1 |
| 30 |
=
| 1 |
| 5 |
| 1 |
| 15 |
| 1 |
| 30 |
=
| 1 |
| 5 |
| 1 |
| 30 |
=
| 1 |
| 6 |
点评:此题考查括号在四则混合运算中的作用:改变运算顺序.
练习册系列答案
相关题目