题目内容
正方形ABCD的边长为1cm,图中4个弓形面积之和是多少?

据分析解答如下:
(
×3.14×12-1×1×
)+(
×3.14×22-2×2×
)+(
×3.14×32-3×3×
)+(
×3.14×42-4×4×
),
=(0.785-0.5)+(3.14-2)+(7.065-4.5)+(12.56-8),
=0.285+1.14+2.565+4.56,
=8.55(平方厘米);
答:图中4个弓形面积之和是8.55平方厘米.
(
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 2 |
=(0.785-0.5)+(3.14-2)+(7.065-4.5)+(12.56-8),
=0.285+1.14+2.565+4.56,
=8.55(平方厘米);
答:图中4个弓形面积之和是8.55平方厘米.
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