题目内容
(1-
)(1-
)…(1-
).
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2009 |
分析:经仔细观察,此题可先算出每个括号的得数,然后通过约分,即可得出结果.
解答:解:(1-
)(1-
)…(1-
),
=
×
×
×…×
×
=
.
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2009 |
=
| 1 |
| 2 |
| 2 |
| 3 |
| 3 |
| 4 |
| 2007 |
| 2008 |
| 2008 |
| 2009 |
=
| 1 |
| 2009 |
点评:解答巧算的题目,应仔细观察,运用运算技巧或运算定律,灵活简算.
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