题目内容
解方程
x=
×
;
x÷
=12; x÷
=
÷
.
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考点:方程的解和解方程
专题:简易方程
分析:①依据等式的性质,方程两边同时
求解;
②依据等式的性质,方程两边同时乘4,再同时乘
求解;
③先化简方程得:x÷
=
,依据等式的性质,方程两边同时
求解.
| 9 |
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②依据等式的性质,方程两边同时乘4,再同时乘
| 3 |
| 2 |
③先化简方程得:x÷
| 6 |
| 35 |
| 10 |
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| 6 |
解答:
解:①
x=
×
x×
=
×
x=
②
x÷
=12
x÷
×
=12×
x=3
x×
=3×
x=4
③x÷
=
÷
.
x÷
×
=
×
x=
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x=
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②
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x=4
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③x÷
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x÷
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| 9 |
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x=
| 4 |
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点评:此题考查了根据等式的性质解方程,即等式两边同加上、同减去、同乘上或同除以一个不为0的数,等式仍相等.同时注意“=”要上下对齐.
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