题目内容
49
×
;
×46+
×28.
| 1 |
| 11 |
| 1 |
| 6 |
| 2 |
| 3 |
| 1 |
| 3 |
分析:(1)把带分数化为假分数,约分计算.
(2)原式变为
×2×46+
×28,运用乘法分配律简算.
(2)原式变为
| 1 |
| 3 |
| 1 |
| 3 |
解答:解:(1)49
×
=
×
=
;
(2)
×46+
×28
=
×2×46+
×28
=
×(92+28)
=
×120
=40.
| 1 |
| 11 |
| 1 |
| 6 |
=
| 540 |
| 11 |
| 1 |
| 6 |
=
| 90 |
| 11 |
(2)
| 2 |
| 3 |
| 1 |
| 3 |
=
| 1 |
| 3 |
| 1 |
| 3 |
=
| 1 |
| 3 |
=
| 1 |
| 3 |
=40.
点评:完成本题要注意分析式中数据,运用合适的简便方法计算.
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