题目内容
(2011?盐亭县)脱式计算,怎样简便就怎样算
①(
-
)÷
+
②
÷
-
×
③
×[
-(
-
)]
④102×
⑤
-
+
-
⑥
÷7+
×
.
①(
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 3 |
| 1 |
| 6 |
②
| 3 |
| 4 |
| 9 |
| 10 |
| 5 |
| 14 |
| 7 |
| 15 |
③
| 8 |
| 9 |
| 3 |
| 4 |
| 7 |
| 16 |
| 1 |
| 4 |
④102×
| 98 |
| 101 |
⑤
| 4 |
| 5 |
| 5 |
| 9 |
| 1 |
| 5 |
| 4 |
| 9 |
⑥
| 8 |
| 13 |
| 1 |
| 7 |
| 5 |
| 13 |
分析:①②③我们按照分数的分数的四则混合运算的顺序进行计算,有括号的先计算括号内部的然后计算括号外面的.
④⑥运用乘法的分配律进行计算会更加简便.
⑤运用加法的结合律、交换律及一个数连续减去两个数可以用这个数减去这两个数的和.
④⑥运用乘法的分配律进行计算会更加简便.
⑤运用加法的结合律、交换律及一个数连续减去两个数可以用这个数减去这两个数的和.
解答:解:①(
-
)÷
+
,
=
×3+
,
=
+
,
=
;
②
÷
-
×
,
=
×
-
×
,
=
-
,
=
;
③
×[
-(
-
)],
=
×[
-
],
=
×
,
=
;
④102×
,
=(101+1)×
,
=101×
+1×
,
=98+
,
=98
;
⑤
-
+
-
,
=(
+
)-(
+
),
=1-1,
=0;
⑥
÷7+
×
,
=
×
+
×
,
=
×(
+
),
=
×1,
=
.
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 3 |
| 1 |
| 6 |
=
| 1 |
| 4 |
| 1 |
| 6 |
=
| 9 |
| 12 |
| 2 |
| 12 |
=
| 11 |
| 12 |
②
| 3 |
| 4 |
| 9 |
| 10 |
| 5 |
| 14 |
| 7 |
| 15 |
=
| 3 |
| 4 |
| 10 |
| 9 |
| 5 |
| 14 |
| 7 |
| 15 |
=
| 5 |
| 6 |
| 1 |
| 6 |
=
| 2 |
| 3 |
③
| 8 |
| 9 |
| 3 |
| 4 |
| 7 |
| 16 |
| 1 |
| 4 |
=
| 8 |
| 9 |
| 3 |
| 4 |
| 3 |
| 16 |
=
| 8 |
| 9 |
| 9 |
| 16 |
=
| 1 |
| 2 |
④102×
| 98 |
| 101 |
=(101+1)×
| 98 |
| 101 |
=101×
| 98 |
| 101 |
| 98 |
| 101 |
=98+
| 98 |
| 101 |
=98
| 98 |
| 101 |
⑤
| 4 |
| 5 |
| 5 |
| 9 |
| 1 |
| 5 |
| 4 |
| 9 |
=(
| 4 |
| 5 |
| 1 |
| 5 |
| 5 |
| 9 |
| 4 |
| 9 |
=1-1,
=0;
⑥
| 8 |
| 13 |
| 1 |
| 7 |
| 5 |
| 13 |
=
| 8 |
| 13 |
| 1 |
| 7 |
| 1 |
| 7 |
| 5 |
| 13 |
=
| 1 |
| 7 |
| 5 |
| 13 |
| 8 |
| 13 |
=
| 1 |
| 7 |
=
| 1 |
| 7 |
点评:本题考查了学生的运算的顺序及运算的定律选用及运用的情况,同时考查了学生的计算能力.
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