题目内容
巧解密码!
=
:30%
(x+
)=4
-
x=
.
| x |
| 4 |
| 1 |
| 3 |
| 2 |
| 5 |
| 1 |
| 3 |
| 3 |
| 4 |
| 1 |
| 4 |
| 1 |
| 3 |
分析:(1)先根据比例基本性质,两内项之积等于两外项之积,化简方程,再依据等式的性质,方程两边同时除以30%求解,
(2)依据等式的性质,方程两边同时除以
,再同时减
求解,
(3)依据等式的性质,方程两边同时加
x,再同时减
,最后同时除以
求解.
(2)依据等式的性质,方程两边同时除以
| 2 |
| 5 |
| 1 |
| 3 |
(3)依据等式的性质,方程两边同时加
| 1 |
| 4 |
| 1 |
| 3 |
| 1 |
| 4 |
解答:解:(1)
=
:30%,
30%x=4×
,
30%x÷30%=
÷30%,
x=4
;
(2)
(x+
)=4,
(x+
)÷
=4÷
,
x+
=10,
x+
-
=10-
,
x=9
;
(3)
-
x=
,
-
x+
x=
+
x,
=
+
x,
-
=
+
x-
,
÷
=
x÷
,
x=1
.
| x |
| 4 |
| 1 |
| 3 |
30%x=4×
| 1 |
| 3 |
30%x÷30%=
| 4 |
| 3 |
x=4
| 4 |
| 9 |
(2)
| 2 |
| 5 |
| 1 |
| 3 |
| 2 |
| 5 |
| 1 |
| 3 |
| 2 |
| 5 |
| 2 |
| 5 |
x+
| 1 |
| 3 |
x+
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 3 |
x=9
| 2 |
| 3 |
(3)
| 3 |
| 4 |
| 1 |
| 4 |
| 1 |
| 3 |
| 3 |
| 4 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 3 |
| 1 |
| 4 |
| 3 |
| 4 |
| 1 |
| 3 |
| 1 |
| 4 |
| 3 |
| 4 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 3 |
| 5 |
| 12 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 4 |
x=1
| 2 |
| 3 |
点评:本题主要考查学生依据等式的性质,以及比例基本性质解方程的能力.
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