题目内容
| 125-25×6÷30 | ( | 1.8+4.3+0.7+4.2 |
| 8.3×9.9+8.3×0.1 | 25×16×50×0.13 |
解:(1)125-25×6÷30
=125-150÷30,
=125-5,
=120;
(2)(
+
)×45
=
+
×45,
=30+6,
=36;
(3)1.8+4.3+0.7+4.2
=(1.8+4.2)+(4.3+0.7),
=6+5,
=11;
(4)8.3×9.9+8.3×0.1
=(9.9+0.1)×8.3,
=10×8.3,
=83;
(5)25×16×50×0.13
=(25×4)×(4×50)×0.13,
=100×200×0.13,
=2600;
(6)
+0.45÷0.9-
=
+0.5-
,
=1-
,
=
.
分析:①(
+
)×45、8.3×9.9+8.3×0.1两式可据乘法分配律进行简便计算;
②1.8+4.3+0.7+4.2可据加法交换律进行简便计算;
③25×16×50×0.13可变为(25×4)×(4×50)×0.13进行计算;
④其余据四则混合运算法则进行计算即可.
点评:完成本题要认真分析各组数据,尽量用简便方法计算.
=125-150÷30,
=125-5,
=120;
(2)(
=
=30+6,
=36;
(3)1.8+4.3+0.7+4.2
=(1.8+4.2)+(4.3+0.7),
=6+5,
=11;
(4)8.3×9.9+8.3×0.1
=(9.9+0.1)×8.3,
=10×8.3,
=83;
(5)25×16×50×0.13
=(25×4)×(4×50)×0.13,
=100×200×0.13,
=2600;
(6)
=
=1-
=
分析:①(
②1.8+4.3+0.7+4.2可据加法交换律进行简便计算;
③25×16×50×0.13可变为(25×4)×(4×50)×0.13进行计算;
④其余据四则混合运算法则进行计算即可.
点评:完成本题要认真分析各组数据,尽量用简便方法计算.
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