题目内容
解方程
|
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x÷
|
x÷
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|
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分析:(1)分数交叉相乘的积相等,然后同时除以36即可得到未知数的值.
(2)方程的两边同时减去
,即可得到未知数的值.
(3)方程的两边同时乘
,即可得到未知数的值.
(4)方程的两边同时乘
,即可得到未知数的值.
(5)首先计算,然后方程两边同时减
,然后再同时乘
;
(6)方程两边同时乘
,然后再两边同时乘2,即可得解.
(2)方程的两边同时减去
| 3 |
| 4 |
(3)方程的两边同时乘
| 4 |
| 15 |
(4)方程的两边同时乘
| 97 |
| 38 |
(5)首先计算,然后方程两边同时减
| 1 |
| 3 |
| 8 |
| 5 |
(6)方程两边同时乘
| 1 |
| 5 |
解答:解:(1)
=
6x×6=25×5
36x÷36=125÷36
x=3
;
(2)
+x=
+x-
=
-
x=
x=
;
(3)x÷
=8
x÷
×
=8×
x=
;
(4)x÷
=19
x÷
×
=19×
x=
;
(5)
x+
×
=1
x+
=1
x+
-
=1-
x×
=
×
x=
;
(6)
x÷
=10
x÷
×
=10×
x×2=2×2
x=4.
| 5 |
| 6x |
| 6 |
| 25 |
6x×6=25×5
36x÷36=125÷36
x=3
| 17 |
| 36 |
(2)
| 3 |
| 4 |
| 8 |
| 9 |
| 3 |
| 4 |
| 3 |
| 4 |
| 8 |
| 9 |
| 3 |
| 4 |
x=
| 8×4-3×9 |
| 36 |
x=
| 5 |
| 36 |
(3)x÷
| 4 |
| 15 |
x÷
| 4 |
| 15 |
| 4 |
| 15 |
| 4 |
| 15 |
x=
| 32 |
| 15 |
(4)x÷
| 97 |
| 38 |
x÷
| 97 |
| 38 |
| 97 |
| 38 |
| 97 |
| 38 |
x=
| 97 |
| 2 |
(5)
| 5 |
| 8 |
| 2 |
| 3 |
| 1 |
| 2 |
| 5 |
| 8 |
| 1 |
| 3 |
| 5 |
| 8 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 3 |
| 5 |
| 8 |
| 8 |
| 5 |
| 2 |
| 3 |
| 8 |
| 5 |
x=
| 16 |
| 15 |
(6)
| 1 |
| 2 |
| 1 |
| 5 |
| 1 |
| 2 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 2 |
x=4.
点评:本题运用等式的基本性质进行解答即可.注意等于号要对齐.
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