题目内容
| 0.1×0.3×0.9+0.2×0.6×1.8+0.3×0.7×2.7 | 0.1×0.2×0.4+0.2×0.4×0.8+0.3×0.6×1.2 |
分析：通过观察，此题数字很有特点，可把原式变为：
，分子、分母可运用乘法分配律计算．
| 0.1×0.3×0.9×13+0.1×0.3×0.9×23+0.1×0.3×0.9×33 |
| 0.1×0.2×0.4×13+0.1×0.2×0.4×23+0.1×0.2×0.4×33 |
解答：解：
，
=
，
=
，
=3
．
| 0.1×0.3×0.9+0.2×0.6×1.8+0.3×0.7×2.7 |
| 0.1×0.2×0.4+0.2×0.4×0.8+0.3×0.6×1.2 |
=
| 0.1×0.3×0.9×13+0.1×0.3×0.9×23+0.1×0.3×0.9×33 |
| 0.1×0.2×0.4×13+0.1×0.2×0.4×23+0.1×0.2×0.4×33 |
=
| 0.1×0.3×0.9×(13+23+33) |
| 0.1×0.2×0.4×(13+23+33) |
=3
| 3 |
| 8 |
点评：此题构思巧妙、新颖别致．要仔细观察，抓住特点，运用所学知识，进行巧妙解答．
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