题目内容
| 3×(150-1530÷15) | [1-( | (1-0.95)÷0.01 |
| | 3.72×99+3.72 | |
解:(1)3×(150-1530÷15)
=3×(150-102)
=3×48
=144;
(2)[1-(
-
)]×
=[1-
]×
=
;
(3)(1-0.95)÷0.01
=0.05÷0.01
=5;
(4)
+(
+
)
=(
+
)+
=1+
=1
;
(5)3.72×99+3.72
=3.72×(99+1)
=3.72×100
=372;
(6)
×140
=
×(139+1)
=
×139+
=111+
=111
;
故答案为144;
;5;1
;372;111
.
分析:(1)可按运算顺序计算;
(2)可按分数四则混合运算的运算顺序进行计算,先算小括号里面的;
(3)先算括号里面的减法,再算除法;
(4)可用加法结合律,先算(
+
)是多少;
(5)可运用乘法分配律进行简便计算;
(6)可把140看成(139+1)后,运用乘法分配律进行简便计算.
点评:此题是考查四则混合运算,要仔细观察算式的特点,灵活运用一些定律进行简便计算.
=3×(150-102)
=3×48
=144;
(2)[1-(
=[1-
=
(3)(1-0.95)÷0.01
=0.05÷0.01
=5;
(4)
=(
=1+
=1
(5)3.72×99+3.72
=3.72×(99+1)
=3.72×100
=372;
(6)
=
=
=111+
=111
故答案为144;
分析:(1)可按运算顺序计算;
(2)可按分数四则混合运算的运算顺序进行计算,先算小括号里面的;
(3)先算括号里面的减法,再算除法;
(4)可用加法结合律,先算(
(5)可运用乘法分配律进行简便计算;
(6)可把140看成(139+1)后,运用乘法分配律进行简便计算.
点评:此题是考查四则混合运算,要仔细观察算式的特点,灵活运用一些定律进行简便计算.
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