题目内容

[(1
2
3
×2+2.5)÷
7
8
-2
1
5
]÷1.6

[(5
1
4
-4.25)×
5
8
3
8
+33÷
11
6

[(9
1
5
-3.2)÷2
1
2
]×[1÷(2.1-2
9
100
)]

9.75+99.75+999.75+9999.75
1
2
3
-[(3.62×
2
15
+6.38÷7
1
2
)×1.82-1
1
3
×0.82]

2890+
5
6
+
7
8
+
7
10
5
6
+
7
8
+
7
10
①[(1
2
3
×2+2.5)÷
7
8
-2
1
5
]÷1.6,
=[(
10
3
+
15
6
)×
8
7
-
11
5
]÷1.6,
=[(
20
6
+
15
6
)×
8
7
-
11
5
5
8

=[
35
6
×
8
7
-
11
5
5
8

=[
20
3
-
11
5
5
8

=[
100
15
-
33
15
5
8

=
67
15
×
5
8

=
67
24

=2
19
24


②[(5
1
4
-4.25)×
5
8
3
8
+33÷
11
6

=
5
8
×
8
3
+33×
6
11

=
5
3
+18,
=19
2
3


③[(9
1
5
-3.2)÷2
1
2
]×[1÷(2.1-2
9
100
)],
=[6×
2
5
]×[1÷
1
100
],
=
12
5
×100

=240;

④9.75+99.75+999.75+9999.75
=(9+1)+(99+1)+(999+1)+(9999+1)-4+0.75×4,
=10+100+1000+10000-4+3,
=11110-1,
=11109;

⑤1
2
3
-[(3.62×
2
15
+6.38÷7
1
2
)×1.82-1
1
3
×0.82],
=1
2
3
-[(3.62×
2
15
+6.38×
2
15
)×1.82-
4
3
×0.82],
=1
2
3
-[
2
15
×(3.62+6.38)×1.82-
4
3
×0.82],
=1
2
3
-[
4
3
×(1.82-0.82)],
=1
2
3
-
4
3

=
1
3


2890+
5
6
+
7
8
+
7
10
5
6
+
7
8
+
7
10

=(2890+
100
120
+
105
120
+
84
120
)÷(
100
120
+
105
120
+
84
120
),
=(2890+
289
120
)×
120
289

=2890×
120
289
+
289
120
×
120
289

=1200+1,
=1201.
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