题目内容
解方程.
|
x-
|
| ||||||||||||||
x-
|
3x-
|
2x+
|
分析:根据解方程的步骤,首先先化简方程,再根据等式的性质进行计算求解即可.
解答:解:(1)
+x=
,
+x-
=
-
,
x=
;
(2)x-
=
,
x-
+
=
+
,
x=
;
(3)
-x=
,
-x-
+x=
-
+x,
x=
-
,
x=
-
,
x=
;
(4)x-
-
=
,
x-
-
+
+
=
+
+
,
x=
;
(5)3x-
=5
,
3x-
+
=5
+
,
3x=6,
3x÷3=6÷3,
x=2;
(6)2x+
=1
,
2x+
-
=1
-
,
2x=1,
x=
.
| 3 |
| 10 |
| 3 |
| 5 |
| 3 |
| 10 |
| 3 |
| 10 |
| 3 |
| 5 |
| 3 |
| 10 |
x=
| 3 |
| 10 |
(2)x-
| 7 |
| 15 |
| 1 |
| 5 |
x-
| 7 |
| 15 |
| 7 |
| 15 |
| 1 |
| 5 |
| 7 |
| 15 |
x=
| 2 |
| 3 |
(3)
| 4 |
| 9 |
| 1 |
| 18 |
| 4 |
| 9 |
| 1 |
| 18 |
| 1 |
| 18 |
| 1 |
| 18 |
x=
| 4 |
| 9 |
| 1 |
| 18 |
x=
| 8 |
| 18 |
| 1 |
| 18 |
x=
| 7 |
| 18 |
(4)x-
| 1 |
| 10 |
| 2 |
| 5 |
| 2 |
| 5 |
x-
| 1 |
| 10 |
| 2 |
| 5 |
| 1 |
| 10 |
| 2 |
| 5 |
| 2 |
| 5 |
| 1 |
| 10 |
| 2 |
| 5 |
x=
| 9 |
| 10 |
(5)3x-
| 1 |
| 7 |
| 6 |
| 7 |
3x-
| 1 |
| 7 |
| 1 |
| 7 |
| 6 |
| 7 |
| 1 |
| 7 |
3x=6,
3x÷3=6÷3,
x=2;
(6)2x+
| 1 |
| 6 |
| 1 |
| 6 |
2x+
| 1 |
| 6 |
| 1 |
| 6 |
| 1 |
| 6 |
| 1 |
| 6 |
2x=1,
x=
| 1 |
| 2 |
点评:本题运用等式的基本性质进行解答即可,考查了学生的计算能力.
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