题目内容
解方程:
0.25x+0.4x+5=31 | (2.75×4+1.25×88)÷12.1. |
分析:(1)先计算0.25x+0.4x=0.65x,等式的两边同时减去5,然后等式的两边同时除以0.65即可;
(2)根据乘法分配律进行计算即可.
(2)根据乘法分配律进行计算即可.
解答:解:
(1)0.25x+0.4x+5=31,
0.65x+5=31,
0.65x+5-5=31-5,
0.65x=26,
0.65x÷0.65=26÷0.65,
x=40;
(2)(2.75×4+1.25×88)÷12.1,
=(11+1.25×8×11)÷12.1,
=(11+10×11)÷12.1,
=11×(1+10)÷12.1,
=11×11÷12.1,
=121÷12.1,
=10.
(1)0.25x+0.4x+5=31,
0.65x+5=31,
0.65x+5-5=31-5,
0.65x=26,
0.65x÷0.65=26÷0.65,
x=40;
(2)(2.75×4+1.25×88)÷12.1,
=(11+1.25×8×11)÷12.1,
=(11+10×11)÷12.1,
=11×(1+10)÷12.1,
=11×11÷12.1,
=121÷12.1,
=10.
点评:本题主要考查解方程,根据等式的性质进行解答即可.
练习册系列答案
相关题目