题目内容
| 已知H2(g)+Cl2(g)=2HCl(g) △H=-184.6kJ·mol-1, 则反应HCl(g)=1/2H2(g)+1/2Cl2(g)的△H为 |
A.+184.6kJ·mol-1 B.-92.3kJ·mol-1 C.-69.2kJ·mol-1 D.+92.3kJ·mol-1 |
试题答案
D已知H2(g)+Cl2(g)=2HCl(g) △H= ―184.6kJ·mol-1,则HCl(g)=1/2H2(g)+1/2Cl2(g)的焓变△H为( )
A.+184.6kJ·mol-1 B.―92.3kJ·mol-1
C.+92.3kJ D.+92.3kJ·mol-1
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已知H2(g)+Cl2(g)=2HCl(g) △H= -184.6kJ·mol-1, 则反应HCl(g)=1/2H2(g)+1/2Cl2(g)的△H为
| A.+184.6kJ·mol-1 | B.―92.3kJ·mol-1 |
| C.+92.3kJ | D.+92.3kJ·mol-1 |
已知H2(g)+Cl2(g)=2HCl(g) △H= -184.6kJ·mol-1, 则反应HCl(g)=1/2H2(g)+1/2Cl2(g)的△H为
A.+184.6kJ·mol-1 B.―92.3kJ·mol-1
C.+92.3kJ D.+92.3kJ·mol-1
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已知H2(g)+Cl2(g)=2HCl(g) △H=―184.6kJ·mol-1, 则反应HCl(g)=1/2H2(g)+1/2Cl2(g)的焓变为( )
A.+184.6kJ·mol-1 B.―92.3kJ·mol-1 C.―369.2kJ·mol-1 D.+92.3kJ·mol-1
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已知H2(g)+Cl2(g)=2HCl(g) △H = ―184.6kJ·mol-1,则HCl(g)=1/2H2(g)+1/2Cl2(g)的焓变△H为 ( )
A.+184.6kJ·mol-1 B.―92.3kJ·mol-1
C.+92.3kJ D. +92.3kJ·mol-1
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已知H2(g)+Cl2(g)=2HCl(g) △H= ―184.6kJ·mol-1, 则反应
HCl(g)=1/2H2(g)+1/2Cl2(g)的△H为
A.+184.6kJ·mol-1 B.―92.3kJ·mol-1
C.+92.3kJ D. +92.3kJ·mol-1[来源:ZXXK]
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已知H2(g)+Cl2(g)=2HCl(g) △H=―184.6kJ·mol-1, 则反应HCl(g)=1/2H2(g)+1/2Cl2(g)的△H为( )
A.+184.6kJ·mol-1 B. ―92.3kJ·mol-1
C. ―369.2kJ·mol-1 D. +92.3kJ·mol-1
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已知H2(g) + Cl2(g) = 2HCl(g) △H= ―184.6kJ·mol-1, 则反应HCl(g) =1/2H2(g) + 1/2Cl2(g)的△H为
A、+184.6kJ·mol-1 B、―92.3kJ·mol-1 C、+92.3kJ D、+92.3 kJ·mol-1
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