摘要:a≥1.单调减
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设a∈[-1,0],已知函数f(x)=
(Ⅰ)证明:函数f(x)在区间(-1,1)内单调递减,在区间(1,+∞)内单调递增;
(Ⅱ)设曲线y=f(x)在点Pi(xi,f(xi))(i=1,2,3)处的切线相互平行,且x1x2x3≠0,试证明:x1+x2+x3>-
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(Ⅰ)证明:函数f(x)在区间(-1,1)内单调递减,在区间(1,+∞)内单调递增;
(Ⅱ)设曲线y=f(x)在点Pi(xi,f(xi))(i=1,2,3)处的切线相互平行,且x1x2x3≠0,试证明:x1+x2+x3>-
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