摘要: 解:(1)设与之间的关系为一次函数.其函数表达式为··················· 1分 将.代入上式得. 解得 ········································································································· 4分 验证:当时..符合一次函数, 当时..也符合一次函数. 可用一次函数表示其变化规律. 而不用反比例函数.二次函数表示其变化规律.···························································· 5分 与之间的关系是一次函数.其函数表达式为································ 6分 (2)当时.由可得 即货车行驶到处时油箱内余油16升.········································································ 8分 (3)方法不唯一.如: 方法一:由(1)得.货车行驶中每小时耗油20升.····················································· 9分 设在处至少加油升.货车才能到达地. 依题意得..···························································· 11分 解得.(升)··································································································· 12分 方法二:由(1)得.货车行驶中每小时耗油20升.····················································· 9分 汽车行驶18千米的耗油量:(升) 之间路程为: 汽车行驶282千米的耗油量: (升)······························································································· 11分 (升)················································································ 12分 方法三:由(1)得.货车行驶中每小时耗油20升.····················································· 9分 设在处加油升.货车才能到达地. 依题意得.. 解得.············································································································· 11分 在处至少加油升.货车才能到达地.·························································· 12分

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