摘要：23．某商场将进价为2000元的冰箱以2400元售出.平均每天能售出8台.为了配合国家“家电下乡 政策的实施.商场决定采取适当的降价措施.调查表明:这种冰箱的售价每降低50元.平均每天就能多售出4台． (1)假设每台冰箱降价x元.商场每天销售这种冰箱的利润是y元.请写出y与x之间的函数表达式,(不要求写自变量的取值范围) (2)商场要想在这种冰箱销售中每天盈利4800元.同时又要使百姓得到实惠.每台冰箱应降价多少元? (3)每台冰箱降价多少元时.商场每天销售这种冰箱的利润最高?最高利润是多少? 解:(1)根据题意.得. 即．······················································································ 2分 (2)由题意.得． 整理.得．················································································ 4分 解这个方程.得．·········································································· 5分 要使百姓得到实惠.取．所以.每台冰箱应降价200元．································· 6分 (3)对于. 当时.······················································································ 8分 ． 所以.每台冰箱的售价降价150元时.商场的利润最大.最大利润是5000元． 10分

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