摘要: 若的展开式的第3项为12.则x等于
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(2012•济南三模)下列正确命题的序号是
(1)“m=-2”是直线(m+2)x+my+1=0与直线(m-2)x+(m+2)y-3=0相互垂直的必要不充分条件;
(2)?a∈R,使得函数y=|x+1|+|x+a|是偶函数;
(3)不等式:
•1≥
•
,
•(1+
)≥
•(
+
),
•(1+
+
)≥
•(
+
+
),…,由此猜测第n个不等式为
(1+
+
+…+
)≥
•(
+
+
)…+
)
(4)若二项式(x+
)n的展开式中所有项的系数之和为243,则展开式中x-4的系数是40.
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(2)(3)
(2)(3)
(1)“m=-2”是直线(m+2)x+my+1=0与直线(m-2)x+(m+2)y-3=0相互垂直的必要不充分条件;
(2)?a∈R,使得函数y=|x+1|+|x+a|是偶函数;
(3)不等式:
| 1 |
| 2 |
| 1 |
| 1 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 3 |
| 1 |
| 5 |
| 1 |
| 3 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 6 |
| 1 |
| n+1 |
| 1 |
| 3 |
| 1 |
| 5 |
| 1 |
| 2n-1 |
| 1 |
| n |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 6 |
| 1 |
| 2n |
(4)若二项式(x+
| 2 |
| x2 |