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n为正偶数时,xn-yn能被x+y整除.
用数学归纳法证明:x2n+1+y2n-1(n∈N*)能被x+y整除.从假设n=k成立到n=k+1成立时,被整除式应为
A.x2k+3+y2k+3
B.x2k+2+y2k+2
C.x2k+1+y2k+1
D.x2k+y2k