摘要：集合A＝{0,2.a}.B＝{1.a2}.若A∪B＝{0,1,2,4,16}.则a的值为( ) A.0 B.1 C.2 D.4 解析:∵A∪B＝{0,1,2.a.a2}.又A∪B＝{0,1,2,4,16}. ∴{a.a2}＝{4,16}.∴a＝4. 答案:D

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