摘要:3.解:记前项的和为.前项的和为.前项的和为. 则成等比数列.即成等比数列. 得.即.
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已知正项数列{an}的前n项和为Sn,且an+
=2Sn,n∈N*.
(Ⅰ)求证:数列{Sn2}是等差数列;
(Ⅱ)求解关于n的不等式an+1(Sn-1+Sn)>4n-8;
(Ⅲ)记数列bn=2Sn3,Tn=
+
+…+
,证明:1-
<Tn<
-
.
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(Ⅰ)求证:数列{Sn2}是等差数列;
(Ⅱ)求解关于n的不等式an+1(Sn-1+Sn)>4n-8;
(Ⅲ)记数列bn=2Sn3,Tn=
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