摘要:25. 解:(1)如图①.过作交于点.则四边形是平行四边形. ∵ .∴ . ∴ . ∴ . 由题意知.当.运动到秒时. ∵ .∴ . ∴ .即 . 解得..············································································································· 5分 (3)分三种情况讨论: ① 当时.如图②.即. ∴ .··················································································································· 6分 ② 当时.如图③.过作于.于H. 则 .. ∴ . ∵ .∴ . ∴ .即 . ∴ .··················································································································· 7分 ③ 当时.如图④.过作于点. 则 . ∵. ∴ . ∴ .即 . ∴ . --------------------------------------------------------------------------8分 综上所述.当.或时.为等腰三角形.

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