摘要:10.CH3CH2CH2CH2CHBrCH2CH2CH3, CH3CH2CH2CH2CH=CHCH2CH,, CH3CH2CH2CH=CHCH2CH2CH3,CH3CH2CH2CHO, CH3CH2CH2CH2OH,CH3CH2CH=CH2. 讲析:由题意C是无支链的醛.D.E也就好推了.将题给信息逆推.两个丁醛中醛基的氧去掉.碳连接起来得到B2.进而求得B1和A.
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