摘要：又y1=x1+m,y2=x2+m, ∴(*)分子=(x1+m-1)(x2-2)+( x2+m -1)(x1-2) =x1x2+(m-2)(x1+x2)-4(m-1)=2m2-4+=0 ∴k1+k2=0.证之．

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