摘要:A.BE=CF B.AC=DFC.∠A=∠D D.AC∥DF
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①BE=CF;②AB•AC=AD•AE;③AD•DF=BD•CD;④AD2+BD2+FD2+CD2=AE2.
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AE=AF或BE=CF或AB=AC
AE=AF或BE=CF或AB=AC
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