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等比数列{an}中,a7?a11=6,a4+a14=5,则=
等比数列{an}中,a7?a11=6,a4+a14=5,则a14-a4=
设向量a,b满足:|a|=3,|b |=4,a?b=0,以a,b,a-b的模为边长构成三角形,则它的边与半径为1的圆的公共点个数最多为