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已知数列{an}满足an=(n∈N*),其前n项和为Sn,则满足不等式|Sn―n―6|<的最小整数n是
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已知数列{an}满足an>0,其前n项和为Sn满足2Sn=+an.
①求an;
②设数列{bn}满足bn=,Tn=b1+b2+…+bn,求证:Tn<2
已知数列{an}满足an>0,其前n项和为Sn满足2Sn=+an满足.
(1)求an;
(2)设数列{bn}满足bn=,Tn=b1+b2+…+bn.求证:Tn<2.