摘要：函数y=log2(x+1)+1(x＞0)的反函数为 A.y=2x-1-1(x＞1) B.y=2x-1+1(x＞1) C.y=2x+1-1(x＞0) D.y=2x+1+1(x＞0) 解析:函数y=log2(x+1)+1(x＞0)的值域为{y|y＞1}.由y=log2(x+1)+1.解得x=2y-1-1. ∴函数y=log2(x+1)+1(x＞0)的反函数为y=2x-1-1(x＞1). 答案:A

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