摘要:以为圆心.并与圆=1相外切的圆的方程 .
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(1)求证:数列{xn}是等比数列,并求数列{xn}的通项公式;
(2)设数列{an}的各项为正,且满足an≤
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| xn+an-1 |
求证:a1x1+a2x2+a3x3+…+anxn<
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| 3n-1 |
(3)对于(2)中的数列{an},当n>1时,求证:(1-an)2[
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(1-
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(1-
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(1-
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1+an+
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