摘要：035]解:(1)(1.0)························································································· 1分 点P运动速度每秒钟1个单位长度．··········································································· 2分 (2) 过点作BF⊥y轴于点.⊥轴于点.则＝8.． ∴． 在Rt△AFB中. 3分 过点作⊥轴于点.与的延长线交于点． ∵ ∴△ABF≌△BCH． ∴． ∴． ∴所求C点的坐标为． 4分 (3) 过点P作PM⊥y轴于点M.PN⊥轴于点N. 则△APM∽△ABF． ∴． ． ∴． ∴． 设△OPQ的面积为 ∴(0≤≤10) ························································ 5分 说明:未注明自变量的取值范围不扣分． ∵<0 ∴当时. △OPQ的面积最大．······························ 6分 此时P的坐标为(.) ．················································································· 7分 (4) 当 或时. OP与PQ相等．························································· 9分 对一个加1分.不需写求解过程．

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