摘要:1×0.5=0.05mol 4.95 ∴ 2:(2Mx-65.39n) = 0.05:4.95 Mx = 99 + (65.39n/2) n = 0.Mx = 99.Tc不合题意,n = 1, Mx =131.70.Xe不合题意, n = 2.Mx = 164.39.Ho不合题意,n = 3, Mx =197.09.Au合题意, ∴X为Au.Y为AuCl3.Z为HAuCl4∙mH2O MAu/(1+MAu+4×35.45+18m)=0.5.解得m=3 ∴ Z为HAuCl4∙3H2O.

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