摘要：22． 解:延长AC交 ON于点E.········································· 1分 ∵AC⊥ON. ∠OEC=90°.································································· 2分 ∵四边形ABCD是矩形. ∴∠ABC=90°.AD=BC. 又∵∠OCE=∠ACB. ∴∠BAC=∠O=25°. ···················································· 3分 在Rt△ABC中.AC=3. ∴BC=AC·sin25°≈1.27 ················································· 5分 ∴AD≈1.27 ································································ 6分 (注:只要考生用其它方法解出正确的结果.给予相应的分值)

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