摘要:19.(1)解:原式=···································································· =······································································· =.······························································································· (2)解:原式=············································································ =·························································································· =1.·········································································································· (3)解:移项.得配方.得····················································· ∴∴······································································ (注:此题还可用公式法.分解因式法求解.请参照给分)
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下面解不等式的过程是否正确?如不正确,请找出错误之处,并改正.
解不等式:
-1<
解:去分母,得5(4-3x)-15<3(7-5x)①
去括号,得20-15x-15<21-15x②
移项、合并,得 5<21③
因为x不存在,所以原不等式无解④
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解不等式:
| 4-3x |
| 3 |
| 7-5x |
| 5 |
解:去分母,得5(4-3x)-15<3(7-5x)①
去括号,得20-15x-15<21-15x②
移项、合并,得 5<21③
因为x不存在,所以原不等式无解④
下面解不等式的过程是否正确?如不正确,请找出错误之处,并改正.
解不等式:
<
解:去分母,得5(4-3x)-15<3(7-5x)①
去括号,得20-15x-15<21-15x②
移项、合并,得 5<21③
因为x不存在,所以原不等式无解④
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阅读以下解题过程,指出错处,说明错误的原因,并改正.
解不等式
≥3+![]()
解:去分母,得2x≥3+5(x-2)
去括号,得2x≥3+5x-10
移项,得2x-5x≥3-10
合并同类项,得-3x≥-7
系数化为1,得x≤-![]()