摘要:.递增.∴.对均成立.∴∴.又.∴最大值为7.
网址:http://m.1010jiajiao.com/timu_id_187618[举报]
设单调递增等比数列{an}满足a1+a2+a3=7,且a3是a1,a2+5的等差中项,
(1)求数列{an}的通项;
(2)数列{cn}满足:对任意正整数n,
+
+…+
=22+
均成立,求数列{cn}的前n项和.
查看习题详情和答案>>
(1)求数列{an}的通项;
(2)数列{cn}满足:对任意正整数n,
| c1 |
| a1 |
| c2 |
| a2 |
| cn |
| an |
| 2n-11 |
| 2n-1 |