摘要: 已知数列{an}中.a1=8, a2 =4且满足an+1-2an+ an-1=0(n∈N*,n≥2).则数列{an}的前 30项的绝对值的和为( ) 830 1512
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已知数列{an}中,a0=2,a1=3,a2=6,且对n≥3时,有an=(n+4)an-1-4nan-2+(4n-8)an-3.
(Ⅰ)设数列{bn}满足bn=an-nan-1,n∈N*,证明数列{bn+1-2bn}为等比数列,并求数列{bn}的通项公式;
(Ⅱ)记n×(n-1)×…×2×1=n!,求数列{nan}的前n项和Sn.
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(Ⅰ)设数列{bn}满足bn=an-nan-1,n∈N*,证明数列{bn+1-2bn}为等比数列,并求数列{bn}的通项公式;
(Ⅱ)记n×(n-1)×…×2×1=n!,求数列{nan}的前n项和Sn.
已知数列{an}中,a0=2,a1=3,a2=6,且对n≥3时,有an=(n+4)an-1-4nan-2+(4n-8)an-3.
(Ⅰ)设数列{bn}满足bn=an-nan-1,n∈N*,证明数列{bn+1-2bn}为等比数列,并求数列{bn}的通项公式;
(Ⅱ)记n×(n-1)×…×2×1=n!,求数列{nan}的前n项和Sn.
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已知数列{an}中,a0=2,a1=3,a2=6,且对n≥3时,有an=(n+4)an-1-4nan-2+(4n-8)an-3.
(Ⅰ)设数列{bn}满足bn=an-nan-1,n∈N*,证明数列{bn+1-2bn}为等比数列,并求数列{bn}的通项公式;
(Ⅱ)记n×(n-1)×…×2×1=n!,求数列{nan}的前n项和Sn.
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(Ⅰ)设数列{bn}满足bn=an-nan-1,n∈N*,证明数列{bn+1-2bn}为等比数列,并求数列{bn}的通项公式;
(Ⅱ)记n×(n-1)×…×2×1=n!,求数列{nan}的前n项和Sn.