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在数列{an}中,a1=2,an+1=an+ln(1+),则an= ( )
A.2+lnn B.2+(n-1)lnn C.2+nlnn D.1+n
在数列
2+lnn
2+(n-1)lnn
2+nlnn
1+n+lnn
在数列{an}中,a1=2,an+1=an+ln(1+),则an=
A.2+lnn
B.2+(n-1)lnn
C.2+nlnn
D.1+n+lnn