摘要:1.已知不等式|2x-t|+t-1<0的解集为.则t=( ) A.0 B.-1 C.-2 D.-3 [解析] ∵|2x-t|<1-t. ∴t-1<2x-t<1-t. 即2t-1<2x<1.t-<x<. ∴t=0. [答案] A
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(海南宁夏卷文1)已知集合M ={ x|(x + 2)(x-1) < 0 },N ={ x| x + 1 < 0 },则M∩N =
A. (-1,1) B. (-2,1) C. (-2,-1) D. (1,2)
查看习题详情和答案>>已知集合M ={ x|(x + 2)(x-1) < 0 },N ={ x| x + 1 < 0 },
则M∩N =( )
A. (-1,1) B. (-2,1)
C. (-2,-1) D. (1,2)
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