摘要:35. [解]设:样品中铁的质量为x.生成铜的质量为y.生成硫酸亚铁的质量为z Fe + CuSO4 = FeSO4 + Cu 56 160 152 64 x 160g×10% z y x = 5.6g y = 6.4g z = 15.2g ···························1 分 (1)a = 5.6g += 6g ····························1 分 (2)5.6g + 160g – 6.4g + 40.8g = 200g

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