摘要:如图(2).P是∠AOB平分线上任意一点.且PD=2cm.若使PE=2cm.则PE与OB的关系是 .
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(1)分别在射线OA、OC上截取线段OD、OE,且OE=2OD;
(2)连接DE;
(3)以O为顶点,画∠DOF=∠EDO,射线OF交DE于点F;
(4)写出图中∠EOF的所有余角:
∠DOF,∠EDO
∠DOF,∠EDO
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